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update post: Closure and this - How are variables resolved within functions?

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2020-08-03 09:33:48 +05:30
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@@ -146,7 +146,7 @@ Before going further, lets take a small detour.
Remember the function scope (`FunctionEnvironment`) and `F.[[ThisMode]]`? Well, this FunctionEnvironment also has 2 internal properties - `env.[[ThisBindingStatus]]` and `env.[[ThisValue]]`. Their values are set based on `F.[[ThisMode]]`. Remember the function scope (`FunctionEnvironment`) and `F.[[ThisMode]]`? Well, this FunctionEnvironment also has 2 internal properties - `env.[[ThisBindingStatus]]` and `env.[[ThisValue]]`. Their values are set based on `F.[[ThisMode]]`.
If `[[ThisMode]]` is lexical, set `[[ThisBindingStatus]]` to 'lexical' and no need of setting `[[ThisValue]]`. If `[[ThisMode]]` is lexical, set `[[ThisBindingStatus]]` to 'lexical' and no need of setting `[[ThisValue]]`.
If `[[ThisMode]]` is non-lexical, set `[[ThisBindingStatus]]` to 'initialized' and set `[[ThisValue]]` to the actual `this` that the function was called with. If `[[ThisMode]]` is non-lexical, set `[[ThisBindingStatus]]` to 'initialized' and set `[[ThisValue]]` to the actual `this` that the function was called with.
In summary, the function scope has 2 properties which say - whether the scope has a `this` value or not and if it has, then what is the value. Arrow functions will not have any `this` value, but normal functions will. In summary, the function scope has 2 properties which say - whether the scope has a `this` value or not and if it has, then what is the value. Arrow functions will not have any `this` value, but normal functions will.